(3x-4)(x^2-2x-1)=0

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Solution for (3x-4)(x^2-2x-1)=0 equation:


Simplifying
(3x + -4)(x2 + -2x + -1) = 0

Reorder the terms:
(-4 + 3x)(x2 + -2x + -1) = 0

Reorder the terms:
(-4 + 3x)(-1 + -2x + x2) = 0

Multiply (-4 + 3x) * (-1 + -2x + x2)
(-4(-1 + -2x + x2) + 3x * (-1 + -2x + x2)) = 0
((-1 * -4 + -2x * -4 + x2 * -4) + 3x * (-1 + -2x + x2)) = 0
((4 + 8x + -4x2) + 3x * (-1 + -2x + x2)) = 0
(4 + 8x + -4x2 + (-1 * 3x + -2x * 3x + x2 * 3x)) = 0
(4 + 8x + -4x2 + (-3x + -6x2 + 3x3)) = 0

Reorder the terms:
(4 + 8x + -3x + -4x2 + -6x2 + 3x3) = 0

Combine like terms: 8x + -3x = 5x
(4 + 5x + -4x2 + -6x2 + 3x3) = 0

Combine like terms: -4x2 + -6x2 = -10x2
(4 + 5x + -10x2 + 3x3) = 0

Solving
4 + 5x + -10x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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